If x + y = 12 and xy = 32, find the value of x^2 + y^2
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5
x^2 and y^2 might be 16 and 64.
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25
Given: x+y=12 and xy=32
Find: x^2 + y^2
Solution:
Since (x+y)^2 = x^2 + y^2 + 2xy
Thus, (12)^2 = (x^2 + y^2) + 2(32)
=> (x^2 + y^2) = (12)^2 - 2(32)
=> x^2 + y^2 = 144 - 64
=> x^2 + y^2 = 80 (answer)
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Find: x^2 + y^2
Solution:
Since (x+y)^2 = x^2 + y^2 + 2xy
Thus, (12)^2 = (x^2 + y^2) + 2(32)
=> (x^2 + y^2) = (12)^2 - 2(32)
=> x^2 + y^2 = 144 - 64
=> x^2 + y^2 = 80 (answer)
Hope it helps you.
Also pls do add it as brainliest.
Thank you
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