Question

if x+y=12 and xy=32
find the value of x^2+y^2

anyone pls answer urgent​

Answer 1

Answer:

Hi mate here's your answer.

Step-by-step explanation:

x + y = 12

(x+y)^2 = x^2 + y^2 + 2xy

(x+y)^2 = 144

2xy = 64

so 144 = x^2 + y^2 + 64

x^2+y^2 = 144 - 64 = 80

Hope you get it.

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Answer 2

Answer:

Step-by-step explanation:

given , x+y=12,xy=32 find x²+y²

then,

x² + y²= (x+y)²- 2xy

           =  (12)²-2×32

            =   144-64

             =   80