Question

if x+y = 12 and xy=32 . find the value of x ^2+ y^2. plz solve its

Answer 1

Given,
x+y=12
xy=32
Now
(x+y)² = x²+y²+2xy
(12)²= x²+y²+2(32)
144= x²+y²+64
Therefore,
x²+y²=144-64=80

Answer 2

Step-by-step explanation:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$