If x+y=12 and xy=32,Find the value of x squared +y squared .
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HOLA MATE HERE IS YOUR ANSWER✌✌✌
X + Y = 12
(X + Y)^2 = 12^2
IDENTITY : X^2 + 2XY + Y^2 = 144
X^2 + 2× 32 + Y^2 = 144
X^2 + 64 + Y^2 = 144
X^2 + Y^2 = 144 - 64
X ^2 + Y^2 = 80
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X + Y = 12
(X + Y)^2 = 12^2
IDENTITY : X^2 + 2XY + Y^2 = 144
X^2 + 2× 32 + Y^2 = 144
X^2 + 64 + Y^2 = 144
X^2 + Y^2 = 144 - 64
X ^2 + Y^2 = 80
HOPE IT HELPS YOU , PLZ MARK AS BRAINLIEST☄☄☄
Answered by
2
Answer:
Step-by-step explanation:
x+y=12
x=12-y-----------equation 1
xy=32
(12-y)y=32 [from 1]
12y-y^2=32
y^2-12y+32=0
y^2-4y-8y+32=0
y(y-4)-8(y-4)=0
y-8=0 y-4=0
y=8 y=4
x=12-8=4 or x=12-4=8
value of x^2+y^2=64
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