Question

if x+y=12 and xy=32,find the value of x2+y2

Answer 1

Answer:

80

Step-by-step explanation:

x+y=12

y=12-x

xy=32

x(12-x)=32

12x-x2=32

x2-12x+32=0

x=(+12+or-√(12)²_4×1×32)÷2×1

x=[12+or-(4)]÷2

x=6+or-(2)

x=8or4

y=12-8=4 or 12-4=8

x2+y2

=64+16=80

or, 16+64=80

Answer 2

Answer:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$

Step-by-step explanation:

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