Question

If x + y = 12 and xy = 32, Find the value of x2 + y2

Answer 1

Step-by-step explanation:

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$( {x + y})^{2} = {x}^{2} + 2xy + {y}^{2} \\ so \\ ( {x + y})^{2} = ( {12})^{2} = 144 \\ {x}^{2} + {y}^{2} = ( {x + y})^{2} - 2xy \\ 144 - 2(32) \\ = 144 - 64 \\ = 80$

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Answer 2

Answer:

it will be:- (8^2)+(4^2)   = 64+16 =80

             :- (8*2)+(4*2)    = 16+8   =24

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Step-by-step explanation:

as x+y=12 the value will be x=8 , y=4

as xy=32 the value of x=8 , y=4

so if the question is x2 + y2

it will be:- (8^2)+(4^2)   = 64+16 =80

             :- (8*2)+(4*2)    = 16+8   =24

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