Math, asked by Anita456, 8 months ago

If x + y = 12 and xy = 32, Find the value of x2 + y2

Answers

Answered by amanraj143
2

Step-by-step explanation:

\huge\tt\underline\red{Answer}

( {x + y})^{2}   =  {x}^{2}  + 2xy +  {y}^{2}  \\ so \\ ( {x + y})^{2}  = ( {12})^{2}  = 144 \\  {x}^{2}  +  {y}^{2}  = ( {x + y})^{2}  - 2xy  \\ 144 - 2(32) \\  = 144 - 64  \\  = 80

<marquee behavior "direction"="up"> hope it helps ✌

Answered by Bhoomipahuja
0

Answer:

it will be:- (8^2)+(4^2)   = 64+16 =80

             :- (8*2)+(4*2)    = 16+8   =24

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Step-by-step explanation:

as x+y=12 the value will be x=8 , y=4

as xy=32 the value of x=8 , y=4

so if the question is x2 + y2

it will be:- (8^2)+(4^2)   = 64+16 =80

             :- (8*2)+(4*2)    = 16+8   =24

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