Math, asked by ag7389502, 7 months ago

if x+y=12 and xy=32 find the value of x2+ y2​

Answers

Answered by saicharanambala
0

Step-by-step explanation:

given x+y=12

square on both sides

we get x^2+y^2+2xy=144

x^2+y^2+2(32)=144

x2+y2=144-2(32)

x2+y2=80

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