Question

if x+y=12 and xy=32 find the value of x2+y2

Answer 1

144=x2+y2+64
144-64=x2+y2
80=x2+y2

Answer 2

Step-by-step explanation:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$