Math, asked by anilkanojiya625, 3 months ago

If x+y = 12 and xy = 32 , find the value of x2 + y2​

Answers

Answered by abhi569
2

Answer:

80

Step-by-step explanation:

Given, x + y = 12

   Square on both sides:

⇒ (x + y)² = 12²

⇒ x² + y² + 2(xy) = 144

⇒ x² + y² + 2(32) = 144    {xy=32}

⇒ x² + y² = 144 - 64

⇒ x² + y² = 80

 Required value of x² + y² is 80

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