If x+y = 12 and xy = 32 , find the value of x2 + y2
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Answer:
80
Step-by-step explanation:
Given, x + y = 12
Square on both sides:
⇒ (x + y)² = 12²
⇒ x² + y² + 2(xy) = 144
⇒ x² + y² + 2(32) = 144 {xy=32}
⇒ x² + y² = 144 - 64
⇒ x² + y² = 80
Required value of x² + y² is 80
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