Question

if x+y = 12 and xy=32, find the value of x2+y2​

Answer 1

Answer:

x²+y²=(x+y)²-2xy

=(12)²-2×32=144-64=80

Step-by-step explanation:

thank you hope it helps you

Answer 2

Answer:

x²+y²=80

Step-by-step explanation:

x²+y²=(x+y)²-2xy

→x²+y²=12²-2×32 [putting the values]

→x²+y²=144-64

→x²+y²=80

Hope it helps you...