Question

. If x + y = 12 and xy = 32, Find the value of x2 + y2

Answer 1

Answer:

Given that: x+y=12 and xy = 32

Using the given identity (x+y)

2

= x

2

+2xy+y

2

⇒ (12)

2

=x

2

+64+y

2

⇒ 144 = x

2

+y

2

+64

⇒ 144−64 = x

2

+y

2

⇒ 80 = x

2

+y

2

The answer is x

2

+y

2

= 80

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