Question

If x + y = 12 and xy=32. Find the value of x² + y²​

Answer 1

Step-by-step explanation:

Hope you got your answer

Answer 2

Answer: The answer is x^2+y^2= 80

Step-by-step explanation:

Given that:  x+y=12 and xy = 32

Using the identity, (x+y)^2= x^2+2xy+y ^2

(12)^2=x^2+64+y^2

144 = x^2+y^2+64

144−64 = x^2+y^2

80 = x^2+y^2

The answer is x^2+y^2= 80