Question

If x+y=12 and xy=32 then find the value of x²+y²

Answer 1

Answer:

x+y = 12 xy=32

( x+y)² = x²+y² + 2xy

(12)² = x²+y² + 2*32

144 = x²+y² + 64

x²+y² = 144 - 64

x²+y² = 80

hope it helps.. plz follow and mark my answer as brainliest...