Math, asked by Anonymous, 5 months ago

If x+y=12 and xy=32 ,then x²+y²=?​

Answers

Answered by Anonymous
7

Answer:

x²+y²= 80

Step-by-step explanation:

x²+y²= (x+y)² - 2xy

by putting the values

x²+y²= (x+y)² - 2xy

= 12 ^2 - 2(32)

= 144 - 64

= 80

hope this helps u dear..

Answered by suhasinipandraju
2

Answer:

x²+y²=80

Step-by-step explanation:

x²+y²=(x+y)²-2xy    [from (X+Y)²=X²+Y²-2XY]

         =(12)²-2(32)

           =144-64

             =80

hope this helps you

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