Question

if x+y=12 and xy=32,then x2+y2=?

Answer 1

thanks for the question

Answer 2

Answer:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}= 144-2×32 \\ x^{2}+y^{2}=80$