Math, asked by mehnaaz19, 1 year ago

if x+y=12 and xy=36, find the value of x^2+y^2​

Answers

Answered by palaktiwary69
5

Answer:

X+y=12

Step-by-step explanation:

squaring both the sides

(X+y)^2=12^2

x^2+y^2+2xy=144

we have the value of xy

so we'll put the value

x^2+y^2+2×36=144

x^2+y^2+72=144

x^2+y^2=144-72

x^2+y^2=72

72 is the answer

hope it helps u

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