if x+y=12 and xy=36, find the value of x^2+y^2
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Answer:
X+y=12
Step-by-step explanation:
squaring both the sides
(X+y)^2=12^2
x^2+y^2+2xy=144
we have the value of xy
so we'll put the value
x^2+y^2+2×36=144
x^2+y^2+72=144
x^2+y^2=144-72
x^2+y^2=72
72 is the answer
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