if x+y=12 and xy=4 find x^2+y^2
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Answered by
2
Answer:
x²+y²
= (x+y)²-2xy
= (12)²-2×4
= 144-8
= 136
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Answered by
1
(X+y)^2=x^2+y^2+2xy
144=x^2+y^2+8
x^2+y^2=136
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