Question

if X+y =12 andxy=32 find the valu of x²+y²​

Answer 1

Answer:

x+y=12

(x+y)²=12²

x²+y²+2xy=144

x²+y²+2(32)=144

x²+y²+64=144

x²+y²= 80

Answer 2

Answer:

80

Step-by-step explanation:

Given that: x+y=12 and xy = 32

Using the identity, (x+y) ^2 = x ^2 +2xy+y^2

⇒ (12) ^2=x^2+64+y^2

⇒ 144 = x^2+y^2+64

⇒ 144−64 = x^2+y^2

⇒ 80 = x^2+y^2

The answer is x^2+y^2=80

Hope this will help you

please try to mark it as brainliest