Question

If x + y = 12 xy = 14, find the value of x^2 + y². ​

Answer 1

Answer:

Given,x+y=12 and xy=14

  x+y=12

Squaring both sides, we get,

  (x+y)2=122

=>x2+y2+2xy=144

=>x2+y2+2(14)=144

=>x2+y2=144−28

=>x2+y2=116

Answer 2

Hence we know the formula by substituting we get 116