Question

if x+y=12 , xy=32 find the value of 1) sum of the square of x and y 2) sum of cubes of x and y​

Answer 1

Answer:

x²+y²=80,x³+y³=576

Step-by-step explanation:

x²+y²=(x+y)²-2xy

        =12²-2(32)

         =144-64

         = 80

x³+y³=(x+y)(x²+y²-xy)

        =(12)(80-32)

          =576

     hope it helps you

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Answer 2

Answer:

x+y=12

xy=32

(x+y) square=xsquare+2xy+ysquare

12 square=xsquare+2*32+Ysquare

144=64+xsquare+ysquare

xsquare+ysquare=144-64

=80

In this way you found the value of xcube+ ycube