Question

If x+y=120 and xy =32, find the value of x2+y2

Answer 1

(x+y)^2=(120)^2

x^2+y^2+2xy=14400

x^2+y^2=14400-2xy

x^2+y^2=14400-2X32

x^2+y^2=14400-64

x^2+y^2=14336

Hope it helps

Answer 2

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