if x+y=12and xy =14 find the value of( x^2+y^2)
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x+y = 12
(x+y)²=144
x²+y²+2xy=144 ______(1)
xy=14
2xy=28 _____(2)
subtracting equation (2) from (1)
x²+y²+2xy-2xy=144-28
x²+y²=116
(x+y)²=144
x²+y²+2xy=144 ______(1)
xy=14
2xy=28 _____(2)
subtracting equation (2) from (1)
x²+y²+2xy-2xy=144-28
x²+y²=116
Answered by
1
answer is( x+y)^2=x^2+y^2+2xy
144_2×14=116
144_2×14=116
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