Question

If X+y =12and XY=32 . Find the value of X*X and y*y

Answer 1

Answer:

x=12-y

XY=32

(12-y)y=32

12y-y^2=32

y^2-12y+32=0

y^2-8y-4y+32=0

y(y-8)-4(y-8)=0

(y-4)(y-8)=0

y=4or 8

if y=4

x+4=12

x=8 or 4

x*x=8*8=64

y*y=4*4=16