If x+y=12and xy =32 find the value of X2+y2
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x+y=12
xy=32
(x+y)²= x²+2xy+y²
⟹(12)²= x²+y²+2xy
⟹144=x²+y²+2×32
⟹144= 64+ x²+y²
⟹x²+y²=144-64
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