Math, asked by aryatripathi58, 2 months ago

if x-y=13 and xy=28 then find the value of x^2+y^2.(x square+ y square)

Answers

Answered by gosved3145
0

Answer:

225

Ans.

Step-by-step explanation:

(x - y) {}^{2}   =  {x}^{2}  +  {y}^{2}  - 2xy \\  (13) {}^{2}  = x {}^{2}  +  {y}^{2}  - 2 \times 28 \\ (13) {}^{2}  =  {x}^{2}  +  {y}^{2}  - 56 \\  {x }^{2}   +  {y}^{2}  = 13 { }^{2}  + 56 \\  {x}^{2}  +  {y}^{2}  = 169 + 56 \\  {x}^{2}  +  {y}^{2}  = 225 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  answer

// Answer. //

Answered by alokkumar78681
1

Answer:

225 is th correct answrt

Step-by-step explanation:

(x-y)2=(13)2

(x)2+(y)2+2xy=169

(x)2 +(y)2=169-2xy

(x)2+(y)2=169-2×28

(x)2+(y)2=169+56

(x)2+(y)2=225

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