Question

- If x-y=13 and xy=28,then find x^2+y^2.​

Answer 1

Answer:

225

Step-by-step explanation:

x-y= 13

xy= 28

(x-y) ²= (13)²

x²-y²= 169

x²-2xy+y²

x²-2xy+y²=169

x²+y²-2*28=169

x²+y²-56=169

x²+y²=169+56

x²+y²= 225

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