If (x - y) = 13 and xy = - 5, then find the value of 1/3(x^2+y^2).
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13x -13y -10/3 (x and y are not solvable) That should be the answer if the question is correct
Step-by-step explanation:
x-y = 13
We can say that x = 13 + y
No put the value of x in 2nd equation
(13 + y) * y = -5
13y + y^2 = -5
y^2 + 13y + 5 = 0
Thus y^2 = -13y-5
Simillary x^2 = 13x - 5
Now 1/3 * ( 13x -5 - 13y -5)
That is equals to 13x -13y -10/3
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