Question

if (x-y) =13 and xy =-5, then find the value of 1/3(x square +y square)​

Answer 1

Answer:

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if (x-y) =13 and xy =-5, then find the value of 1/3(x square +y square)

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ans refer to attachment

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Answer 2

Hello, Buddy!!

||Required Response||

By Equating

→ (a-b)² = (a+b)²

→ (a-b)² = a²+b²+2ab

→ a²+b² = (a-b)²+2ab

→ a²+b² = a²+b²-2ab+2ab

→ a²+b² = a²+b²

Now,

${x}^{2} + {y}^{2} = {(x - y)}^{2} + 2(xy) \\ {x}^{2} + {y}^{2} = {(13)}^{2} + 2( - 5) \\ {x}^{2} + {y}^{2} = 169 - 10 \\ {x}^{2} + {y}^{2} = 159$

→ 1/3(x²+y²)

→ 1/3(159)

→ 53

• Required Value ☞ 53

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