Question

If (x + y) = 13 and xy = - 5, then find the value of 1\3 (x² + 1/x²)​

Answer 1

Step-by-step explanation:

Given, x−y=13 and xy=28

We know that, (x−y)

2

=x

2

+y

2

−2xy ... (i)

By putting the given values in equation (i),

(13)

2

=x

2

+y

2

—2(28)

169=x

2

+y

2

−56

169+56=x

2

+y

2

225=x

2

+y

2

So, the value of x

2

+y

2

is 225.