Question

If (x-y) =13 and xy= -5,then find the values of ⅓(x²+y²)​

Answer 1

Answer:

53

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

X-Y=13 & XY=-5, then 1/3(x-y)^2=?

It is given that x-y =13 & x-y =-5

We know that (x-y)^2 =x^2+y^2-2xy

Then,

(13)^2=x^2+ y^2 -2*-5

169=x^2+y^2-10

X^2+Y^2=159

PUTTING THE VALUE WE GET

1/3(X^²+Y^2)= 1/3*159

SO WE GET 53 AS ANSWER