if x+y=13 and xy=6whole1/4, find x-y
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Answer:
13×1999=82261
Step-by-step explanation:
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Answered by
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Answer:
If x+y=13 and xy=25/4 then we can calculate x-y by using some identities
We know that (x+y)^2 - 4*xy = (x-y)^2
There for by substituting the values for x+y and xy we be the value of (x-y)^2=144
This implies that x-y=12
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