Question

If x + y =13 and xy =7, then find the value of x^2 + y^2​

Answer 1

Step-by-step explanation:

(x+y) ^2= x^2+y^2+2xy

(13) ^2 = x^2+y^2+2×7

169 = x^2+y^2+14

x^2+y^2=169-14

x^2+y^2=155

Answer 2

Answer:

155

Step-by-step explanation:

since, x + y = 13 and xy = 7

we know that (x + y)^2 = x^2 + y^2 +2xy

(x+y) ^2= (13)^2+2×7

(x+y)^2= 169-14

(x+y) ^2= 155