If x + y =13 and xy =7, then find the value of x^2 + y^2
Answers
Answered by
2
Step-by-step explanation:
(x+y) ^2= x^2+y^2+2xy
(13) ^2 = x^2+y^2+2×7
169 = x^2+y^2+14
x^2+y^2=169-14
x^2+y^2=155
Answered by
0
Answer:
155
Step-by-step explanation:
since, x + y = 13 and xy = 7
we know that (x + y)^2 = x^2 + y^2 +2xy
(x+y) ^2= (13)^2+2×7
(x+y)^2= 169-14
(x+y) ^2= 155
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