If x+y=14 and xy=16,find the value of x ²+ y ²
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Answered by
2
Given
x + y = 14
take square both side ,we get,
( x + y )^2 = 196
x^2 + y^2 + 2xy = 196
given, xy = 16
x^2 + y^2 + 2(16) =196
x^2 + y^2 = 196 - 32
x^2 + y^2 = 164
hope it helps
x + y = 14
take square both side ,we get,
( x + y )^2 = 196
x^2 + y^2 + 2xy = 196
given, xy = 16
x^2 + y^2 + 2(16) =196
x^2 + y^2 = 196 - 32
x^2 + y^2 = 164
hope it helps
aryan5496:
who will square 14 on the right side.
accidentally it took place but i corrected it in a jiffy .
Answered by
2
(x+y)^2 = x^2 + y^2 + 2xy
(14)^2 = x^2 + y^2 + 2x16
196-32= x^2+y^2
x^2 + y^2 = 164.
(14)^2 = x^2 + y^2 + 2x16
196-32= x^2+y^2
x^2 + y^2 = 164.
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