if x+y=14 and xy=16,find the value of x²+y².
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Answered by
15
x^2+y^2
= (x+y)^2- 2xy
As x+y=14 and xy=16
So x^2+y^2
= (14)^2-32
= 196-32
= 164
= (x+y)^2- 2xy
As x+y=14 and xy=16
So x^2+y^2
= (14)^2-32
= 196-32
= 164
Answered by
31
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