Question

if x+y=-1then what is the value of x^3+y^3-3xy

Answer 1

X+y=-1
Cubing on both sides
So
(X+y)³=-1³
X³+y³+3xy(x+y)=-1
X³+y³+3xy(-1)=-1
X³+y³-3xy=(-1)
X³+y³-3xy=-1




I hope this will help u
By DEVANSH

Answer 2

hope this helps you!!!!!