If x+y+2=0, then find the value of x cube + y cube+ 8
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Answered by
2
Given,
x + y + 2 = 0
x + y = -2
Cubing on both sides
x³+y³+3xy(x+y) = -8
x³+y³+3xy(-2) = -8
x³+y³+8 = 6xy .
Therefore, Required answer is 6xy .
hope helped!
x + y + 2 = 0
x + y = -2
Cubing on both sides
x³+y³+3xy(x+y) = -8
x³+y³+3xy(-2) = -8
x³+y³+8 = 6xy .
Therefore, Required answer is 6xy .
hope helped!
Answered by
2
Hey,
The given equation is x+y+2=0 ....(1)
x+y+2=0
x+y=−2
(x+y)3=(−2)^3
x^3+y^3+3xy(x+y)=−8x^3+y^3+3xy*(−2)
=−8x^3+y^3−6xy
=−8x^3+y^3+8
=6xy
HOPE IT HELPS:-))
The given equation is x+y+2=0 ....(1)
x+y+2=0
x+y=−2
(x+y)3=(−2)^3
x^3+y^3+3xy(x+y)=−8x^3+y^3+3xy*(−2)
=−8x^3+y^3−6xy
=−8x^3+y^3+8
=6xy
HOPE IT HELPS:-))
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