Question

If x+y+2=0 then write the value of x^3+y^3+8

Answer 1

Answer:

We know,

If a + b + c = 0 then, a³ + b³ + c³ = 3abc

Because a³ + b³ + c³ = 1/2(a + b + c ) (a² + b² + c² - ab - bc - ca)

Now, when a + b + c = 0 then, a³ + b³ + c³ - 3abc = 0

so, a³ + b³ + c³ = 3abc

Here, x + y + 2 = 0

so, x³ + y³ + 2³ = 3xy(2)

x³ + y³ + 8 = 6xy

Hence, the answer id 6xy.

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Answer 2

Answer:

6xy

Step-by-step explanation:

Answer:Given x+y+2=0,then

x3+y3+8=(x)3+(y)3+(2)3=0

=>We know if a+b+c=0,then

a3+b3+c3=3abc

=>x3+y3+(2)3=3.x.y.2

=>x3+y3+8=6xy

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