Question

if X + y + 2 = 0 then x^3 + y^3 + 2^3 is​

Answer 1

Given that;

x+y+2=0…(1)      

To find:

x  

3

+y  

3

+8=?

Taking cube on both sides of (1):

(x+y+2)  

3

=0

x  

3

+y  

3

+8(x+y+2)(xy+2y+2x)=0.

x  

3

+y  

3

+8+(0)(xy+2y+2x)=0

x  

3

+y  

3

+8=0