If [x y]=2[ 1/ 2 8] , find the value of x and y.
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Answer:
2[
1
0
3
x
]+[
y
1
0
2
]=[
5
1
6
8
].
[
2
0
6
2x
]+[
y
1
0
2
]=[
5
1
6
8
]
[
2+y
1
6
2x+2
]=[
5
1
6
8
]
comparing corresponding elements we get,
2+y=5⇒
y=3
2x+2=8⇒2x=6⇒
x=3
∴x=3,y=3
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