Math, asked by hitenderverma2856, 5 months ago

If X:y=2:1, find x^2-y^2:x^2+y^2

Answers

Answered by dsharma5902p3xbhp
1

Answer:

3/5

Step-by-step explanation:

x/y= 2/1

x/y= 2k/1k

=> x=2k , y=1k

(x²-y²)/(x²+y²)=[ (2k)²-(k) ²] / [ (2k)² +(k) ²]

= 4k²-k²/ 4k²+k²

= 3k²/5k²

= 3/5

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Answered by naveenauday
1
x/y=2/1. Put x=2y.


4y^2-y^2/4y^2+y^2


3y^2/5y^2=3/5

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