if x/y=2/1,y/z=4/1 find (x⁴/32y²z²)³
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Answer:
x/y=2/1
y/z=4/1
x/y*y/z=2/1.4/1
x/z=8/1
(x⁴/32y²z²)³
=1/32³*((x/y) ²)³((x/z)²)³
=1/32³*2³*8³
=1/32³*16³
=(1/2³*16³)*16³
=1/2³
=1/8
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