If (x+y)^2=105 and x^2+y^2=65, what is the value of xy ?
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Answered by
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(x + y) ^2 = 105
x^2 + 2xy + y^2 = 105
x^2 + y^2 + 2xy = 105
{Given that } x^2 + y^2 = 65,
65 + 2xy = 105
2xy = 105 - 65
2xy = 40
xy = 20
{Answer: xy = 20]
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Answered by
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x^2+y^2+2xy=105
65+2xy=105
2xy=40
xy=20
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