Question

if (x-y)² = 121xy , then 2log (x+y) = ​

Answer 1

*Question:—

if (x-y)² = 121xy , then 2log (x+y) = ?

*Answer:—

From [1] :—

→ (x - y)² = 121xy

→ x² + y² - 2xy = 121xy

→ x² + y² + 2xy = 125xy

→ (x + y)² = 125xy

Applying log on both the sides :—

→ log(x + y)² = log(125xy)

→ 2log(x + y) = log125 + log(x) + log(y) ____[3]

From [2] and [3] :—

→ k = log25

Hope it helps you.

$@vikramjeeth$