Question

If (x+y-2)^2+3x-2y-1)^2=0, then the values of x and y are respectively

Answer 1

$\sf \blue{(x+y-2)2 + ( 3x-2y-1) 2=0} \\ </h3><h3> \sf \green{2x+2y-4 +6x-4y-2 =0} \\ </h3><h3> \sf \pink{8x-2y+6=0}$

Now,

let put X= -1 and y= -1

Then,

$\sf \red{8(-1)-2(-1)+6=0} \\ </h3><h3> \sf \purple{-8+2+6=0} \\ </h3><h3> \sf \orange{-8+8=0} \\ </h3><h3> \sf \blue{0=0}$