Math, asked by renu07397gmailcom, 25 days ago

if x/y = {-2/3} ^3 ÷{8/3}^3 find the value of {y/x}^2

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Answered by sk9411531

Answer:

H + Till 11:20 = = 2y2 = + y2 + x2 - y2 17 + 8 x2 + y2 – x2 + y2 17-8 2x2 25 9 259 X 5 y 3 X : y = 5 : 3 X 5 ( ii ) y 3 Taking cube on both sides , x3 125 27 = 13

Answered by pbhagirath1954

(y/x)² = 64

the explanation is given in the attachment, plz mark as the brainliest

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if x/y = {-2/3} ^3 ÷{8/3}^3 find the value of {y/x}^2​

Answers

if x/y = {-2/3} ^3 ÷{8/3}^3 find the value of {y/x}^2