Math, asked by ahnafhdbwidh, 4 months ago

If x:y=2:3 and y:z=3:4, find x:z.

2. The length of the rectangle is 5 cm more than its breadth. If the perimeter of the rectangle is 62cm, find it's area.

Answers

Answered by navneetnayan811
0

Answer:

1 . 1/2

2: 234 squre cm

Step-by-step explanation:

1.

sol:

x/y * y/z

= 2/3 * 3/4

= 1/2

so, x:z =1:2

Ans:1:2

2.

sol:

Given,

perimeter- 62cm

Let, Breadth = x cm

length. = (x+5)cm

perimeter of rectangle =2(l+b)

62cm = 2(x+5+x) cm

Or, 62cm/2cm =2x+5

Or, 31-5 =2x

Or, 26 =2x

Or, 26/2 = x

Or, 13 = x

So,

Breadth =13cm &

Length = (13 +5)cm

=18cm

Hence,

Area of rectangle = l * b

= 18cm*13cm

= 234 square cm

Ans: 234 square cm

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