Question

If x:y=2:3, find the value of (3x + 2 y):(2x+5y)​

Answer 1

Answer:

If x:y = 2:3

Then x=2, y=3

(3x+2y):(2x+5y)

Now putting the values,

(3×2+2×3):(2×2+4×3)

(6+6):(4+12)

12:16

=12/16

= 3/4

= 3:4

There correct answer is 3:4

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Answer 2

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$x \:\ratio\: y = 2\ratio3 = \frac{x}{y} = \frac{2}{3 }$

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$(3x + 2y)\ratio(2x + 5y) \\ ⟹ \frac{3x + 2y}{2x + 5y} \ = \frac{ \frac{3x + 2y}{y} }{ \frac{2x + 5y}{y} } \: [dividing \: numerator \: and \: denominator \: by \: y \: ] \\ ⟹ \frac{3( \frac{x}{y} ) + 2}{2 (\frac{x}{y} ) + 5} = \frac{3 \times \frac{2}{3} + 2}{2 \times \frac{2}{3} + 5 } \\ ⟹ \frac{2 + 2}{ \frac{4}{3} + 5 } = \frac{4}{ \frac{19}{3} } = \frac{12}{19} = 12\ratio19$

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