if (x+y)² =73 and xy= 65, find the value of x²
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Answered by
0
Answer:
the answer might be monus 58 minus y square
Answered by
1
Step-by-step explanation:
(x+y)^2=73
x^2+2xy+y^2 =73
x^2+2(65)+y^2 = 73
x^2+130+y^2 = 73
x^2 + y^2 = 73-130
x^2 = -57- y^2
or x^2 = -(57+y^2)
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