Math, asked by levyy, 5 months ago

if (x+y)² =73 and xy= 65, find the value of x²​

Answers

Answered by AwesomeBoyzzzzzzz
0

Answer:

the answer might be monus 58 minus y square

Answered by devangnivasava
1

Step-by-step explanation:

(x+y)^2=73

x^2+2xy+y^2 =73

x^2+2(65)+y^2 = 73

x^2+130+y^2 = 73

x^2 + y^2 = 73-130

x^2 = -57- y^2

or x^2 = -(57+y^2)

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