If x/y = [(2/9)³]²*[(2/9)²]³ find (x/y)³+(x/y)5
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=(x+y)3−(x−y)3−6y(x2−y2)
=(x+y)3−(x−y)3−6y(x−y)(x+y)
=(x+y)3−(x−y)((x−y)2+6y(x+y))
=(x+y)3−(x−y)(x2+y2−2xy+6xy+6y2)
=(x+y)3−(x−y)(x2+7y2+4xy)
=x3+y3+3x2y+3xy2−x3−7xy2−4x2y+x2y+7y3+4xy2
=8y3
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