Math, asked by supalibhattacharya20, 8 months ago

if x+y =2 and 1/x+1/y =2 find the value of x3+y3

Answers

Answered by iftishakhatun

1

Answer:

x+y+2 = 0 x

3

+y

3

+8

Taking cube not on both sides

(x+y+2)

3

=0

x

3

+y

3

+8(x+y+2)(xy+2y+2x)=0.

x

3

+y

3

+8+(0)(xy+2y+2x)=0

x

3

+y

3

+8=0

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